Maximum Value
2017/07/04 16:54
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Maximum Value
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Z = 1000y(52 + x) / (15x + 365) Z = y(52000 + 1000x) / (15x + 365) Z = y[(200/3)(15x + 365) + 83000/3] / (15x + 365) Z = y[200/3 + 83000/(45x + 1095)] Z is maximum when y is maximum and x is a minimum The values are x = 0, y = 14, Z max = 14(200/3 + 83000/1095) = 145600 / 73 = 1994.52
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Maximum Value
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Z = 1,000y(52 + x)/(15x + 365) where 0 < x < 1 and 0< y < 14. At what value of x and y that Z is a maximum? What is Z max.?最佳解答:
Z = 1000y(52 + x) / (15x + 365) Z = y(52000 + 1000x) / (15x + 365) Z = y[(200/3)(15x + 365) + 83000/3] / (15x + 365) Z = y[200/3 + 83000/(45x + 1095)] Z is maximum when y is maximum and x is a minimum The values are x = 0, y = 14, Z max = 14(200/3 + 83000/1095) = 145600 / 73 = 1994.52
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