math!!!
2017/06/24 15:37
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標題:
math!!!
發問:
1. two cars are travelling in the same direction on a road. the car that leads is traveling at 46 miles per hour. the other car is traveling at 70 miles per hour. how many miles apart will they be 30 minutes before the faster car catches the slower one? 更新: 2. an alarm clock runs 4 minutes slow every hour. it was set right 3 and half hours ago. now another clock, which is correct, shows noon. in how many minutes, to the nearest minute, will the alarm clock show noon?
最佳解答:
Q1. Let the car that leads be Car A and the other car, be Car B When Car B catches up with Car A, they will 0 miles apart. 30 minutes before that, Car A will be 46/2=23 miles behind 30 minutes before that, Car B will be 70/2=35 miles behind The difference between them will be 35-23 = 12 miles apart. ---------------------------------------------------------------------------------------------- Q2. Since the incorrect alarm clock runs 4 minutes slow per hrs, in 3.5 hrs, it would be 3.5*4=14 minutes slower. Since the clock runs 4 minutes slower every hr, Thus, in 14 minutes time, it would be 14/60*4 minutes slower ~ = 0.93 minutes Thus, the alarm clock will show noon in 14.93 minutes ~= 15minutes
math!!!
發問:
1. two cars are travelling in the same direction on a road. the car that leads is traveling at 46 miles per hour. the other car is traveling at 70 miles per hour. how many miles apart will they be 30 minutes before the faster car catches the slower one? 更新: 2. an alarm clock runs 4 minutes slow every hour. it was set right 3 and half hours ago. now another clock, which is correct, shows noon. in how many minutes, to the nearest minute, will the alarm clock show noon?
最佳解答:
Q1. Let the car that leads be Car A and the other car, be Car B When Car B catches up with Car A, they will 0 miles apart. 30 minutes before that, Car A will be 46/2=23 miles behind 30 minutes before that, Car B will be 70/2=35 miles behind The difference between them will be 35-23 = 12 miles apart. ---------------------------------------------------------------------------------------------- Q2. Since the incorrect alarm clock runs 4 minutes slow per hrs, in 3.5 hrs, it would be 3.5*4=14 minutes slower. Since the clock runs 4 minutes slower every hr, Thus, in 14 minutes time, it would be 14/60*4 minutes slower ~ = 0.93 minutes Thus, the alarm clock will show noon in 14.93 minutes ~= 15minutes
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