F4 Maths...我有咩錯!
2017/06/24 21:26
瀏覽123
迴響0
推薦0
引用0
標題:
F4 Maths...我有咩錯!
發問:
If the quadratic equation 4x^2-gx+15=0 has two distinct real roots which of the following are the possible values of g? solution: Because the quadratic equation 4x^2-gx+15=0 has two distinct real roots ∴ △﹥0 4x^2-gx+15﹥0 (-g)^2-4(4)(15)﹥0 g^2-240﹥0 g^2﹥240 g﹥±15.49...
最佳解答:
solution: Because the quadratic equation 4x^2-gx+15=0 has two distinct real roots ∴ △﹥0 4x^2-gx+15﹥0 (-g)^2-4(4)(15)﹥0 g^2-240﹥0 g^2﹥240 g﹥±15.49... 4x^2-gx+15﹥0 這句是wrong 的 g^2﹥240 (g+15.49)(g-15.49)>0 g<-15.49 or g>15.49
其他解答:
F4 Maths...我有咩錯!
發問:
If the quadratic equation 4x^2-gx+15=0 has two distinct real roots which of the following are the possible values of g? solution: Because the quadratic equation 4x^2-gx+15=0 has two distinct real roots ∴ △﹥0 4x^2-gx+15﹥0 (-g)^2-4(4)(15)﹥0 g^2-240﹥0 g^2﹥240 g﹥±15.49...
最佳解答:
solution: Because the quadratic equation 4x^2-gx+15=0 has two distinct real roots ∴ △﹥0 4x^2-gx+15﹥0 (-g)^2-4(4)(15)﹥0 g^2-240﹥0 g^2﹥240 g﹥±15.49... 4x^2-gx+15﹥0 這句是wrong 的 g^2﹥240 (g+15.49)(g-15.49)>0 g<-15.49 or g>15.49
其他解答:
此文章來自奇摩知識+如有不便請留言告知
你可能會有興趣的文章：
限會員,要發表迴響,請先登入
