About p6 math(10marks)
2017/07/04 12:37
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About p6 math(10marks)
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10/0.8Here is cups 21杯,用了14杯,餘下未用的佔全部幾分之幾? 61 1/2÷1 1/2 (3 5/8+6 1/6)÷2 11/12 糖水原有8.6ml,取了3.8ml,又加回1.5ml,現在有糖水多少ml
最佳解答:
1) 未用的杯=7, 杯的總數=21, 未用的佔7/21=1/3 2) 61 1/2÷1 1/2 =123/2*2/3 41 3) (3 5/8+6 1/6)÷2 11/12 =(29/8+37/6)*12/35 =(87/24+148/24)*12/35 =235/24*12/35 =47/14 =3 5/14 4) 原有8.6ml,取了3.8ml,又加回1.5ml, 現在有糖水=8.6-3.8+1.5=6.3ml
10 / 0.8 = 100 / 8 = 25 / 2 = 12 1/2 (=12.5) ------------------------------------------------------------------------------ 有21杯,用了14杯, 餘下了 21 - 14 = 7杯 佔全部21杯的 7/21 = 1/3 ------------------------------------------------------------------------------ 61 1/2÷1 1/2 = 123 / 2 ÷ 3 / 2 = 123 / 2 x 2 / 3 = 123 / 3 = 41 ------------------------------------------------------------------------------ (3 5/8+6 1/6)÷2 11/12 =(29/8 + 37/6) ÷ 35/12 = (87/24 + 148/24) x 12/35 = 235/24 x 12/35 = 47/14 = 3 5/14 ------------------------------------------------------------------------------ 糖水原有8.6ml,取了3.8ml,又加回1.5ml, 現在有糖水 8.6 - 3.8 + 1.5 = 6.3ml (=6 3/10)
About p6 math(10marks)
發問:
10/0.8Here is cups 21杯,用了14杯,餘下未用的佔全部幾分之幾? 61 1/2÷1 1/2 (3 5/8+6 1/6)÷2 11/12 糖水原有8.6ml,取了3.8ml,又加回1.5ml,現在有糖水多少ml
最佳解答:
1) 未用的杯=7, 杯的總數=21, 未用的佔7/21=1/3 2) 61 1/2÷1 1/2 =123/2*2/3 41 3) (3 5/8+6 1/6)÷2 11/12 =(29/8+37/6)*12/35 =(87/24+148/24)*12/35 =235/24*12/35 =47/14 =3 5/14 4) 原有8.6ml,取了3.8ml,又加回1.5ml, 現在有糖水=8.6-3.8+1.5=6.3ml
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其他解答:10 / 0.8 = 100 / 8 = 25 / 2 = 12 1/2 (=12.5) ------------------------------------------------------------------------------ 有21杯,用了14杯, 餘下了 21 - 14 = 7杯 佔全部21杯的 7/21 = 1/3 ------------------------------------------------------------------------------ 61 1/2÷1 1/2 = 123 / 2 ÷ 3 / 2 = 123 / 2 x 2 / 3 = 123 / 3 = 41 ------------------------------------------------------------------------------ (3 5/8+6 1/6)÷2 11/12 =(29/8 + 37/6) ÷ 35/12 = (87/24 + 148/24) x 12/35 = 235/24 x 12/35 = 47/14 = 3 5/14 ------------------------------------------------------------------------------ 糖水原有8.6ml,取了3.8ml,又加回1.5ml, 現在有糖水 8.6 - 3.8 + 1.5 = 6.3ml (=6 3/10)
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