Reacting Masses
2017/07/04 08:02
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1. Find the empirical formula of a compound of 43.4% sodium, 11.3% carbon and 45.3% oxygen by mass.2. The composition percentage by mass of compound Y is Zn : 40.5%; S : 19.85%and O : 39.65%. Find its empirical formula.3. On reduction, 0.36g of an oxide gives 0.31g of lead. Find the empirical formula of the... 顯示更多 1. Find the empirical formula of a compound of 43.4% sodium, 11.3% carbon and 45.3% oxygen by mass. 2. The composition percentage by mass of compound Y is Zn : 40.5%; S : 19.85%and O : 39.65%. Find its empirical formula. 3. On reduction, 0.36g of an oxide gives 0.31g of lead. Find the empirical formula of the oxide. 4. Copper oxide is reduced by hydrogen. What mass of copper will be produced from : 3.6g of copper(II) oxide ?
最佳解答:
1. Mole ratio Na : C : O = 43.4/23 : 11.3/12 : 45.3/16 = 1.89 : 0.942 : 2.83 = 2 : 1 : 3 Empirical formula = Na2CO3 ==== 2. Mole ratio Zn : S : O = 40.5/65.4 : 19.85/32 : 39.65/16 = 0.619 : 0.620 : 2.48 = 1 : 1 : 4 Empirical formula = ZnSO4 ==== 3. Mass of Pb = 0.31 g Mass of O = 0.36 - 0.31 = 0.05 g Mole ratio Pb : O = 0.31/207 : 0.05/16 = 0.00150 : 0.00313 = 1 : 2 Empirical formula = PbO2 ==== 4. Mass of 1 mole of CuO = 63.5 + 16 = 79.5 g Mass of Cu in 1 mole CuO = 63.5 g Mass of Cu produced = 3.6 × (63.5/79.5) = 2.88 g
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Reacting Masses發問:
1. Find the empirical formula of a compound of 43.4% sodium, 11.3% carbon and 45.3% oxygen by mass.2. The composition percentage by mass of compound Y is Zn : 40.5%; S : 19.85%and O : 39.65%. Find its empirical formula.3. On reduction, 0.36g of an oxide gives 0.31g of lead. Find the empirical formula of the... 顯示更多 1. Find the empirical formula of a compound of 43.4% sodium, 11.3% carbon and 45.3% oxygen by mass. 2. The composition percentage by mass of compound Y is Zn : 40.5%; S : 19.85%and O : 39.65%. Find its empirical formula. 3. On reduction, 0.36g of an oxide gives 0.31g of lead. Find the empirical formula of the oxide. 4. Copper oxide is reduced by hydrogen. What mass of copper will be produced from : 3.6g of copper(II) oxide ?
最佳解答:
1. Mole ratio Na : C : O = 43.4/23 : 11.3/12 : 45.3/16 = 1.89 : 0.942 : 2.83 = 2 : 1 : 3 Empirical formula = Na2CO3 ==== 2. Mole ratio Zn : S : O = 40.5/65.4 : 19.85/32 : 39.65/16 = 0.619 : 0.620 : 2.48 = 1 : 1 : 4 Empirical formula = ZnSO4 ==== 3. Mass of Pb = 0.31 g Mass of O = 0.36 - 0.31 = 0.05 g Mole ratio Pb : O = 0.31/207 : 0.05/16 = 0.00150 : 0.00313 = 1 : 2 Empirical formula = PbO2 ==== 4. Mass of 1 mole of CuO = 63.5 + 16 = 79.5 g Mass of Cu in 1 mole CuO = 63.5 g Mass of Cu produced = 3.6 × (63.5/79.5) = 2.88 g
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