phy 問題!about heat
2017/06/29 08:05
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phy 問題!about heat
a piece of copper of mass 0.5kg at 100度 is put into 0.2kg of water at 20度. the final temperature of the mixture of copper and water is 35度. assume there is no heat loss to the surrounding. what is the specific heat capacity of copper??
最佳解答:
Energy loss by copper=Energy gained by water 0.5*specific heat capacity of copper *(100-35)=0.2*4200*(35-20) 32.5*specific heat capacity of copper =12600 specific heat capacity of copper =12600/32.5 =387.6(corr to 1 decimal place) **specific heat capacity of water=4200J/kg ℃ 2006-11-15 22:44:11 補充: sor~~answer should be 387.7(corr to 1 decimal place)
其他解答:
mcT=mcT 所有mixture只要將兩樣野既mcT =佢地,跟住就可以搵番剩低要既data 0.5kg(100度-35度)c=0.2kg(4200)(35度-20度) 50c-17.5c=29400-16800 32.5c=12600 c=388Jkg-1度-1(cor. to 3 sig.fig.) 2006-11-15 22:51:13 補充: specific heat capacity of water=4200Jkg-1度-1唔記得左講番佢地=既原因係:一開始copper比water熱所以copper有energy losswater就有energy gainenergy loss of copper=energy gain of water
phy 問題!about heat
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發問:a piece of copper of mass 0.5kg at 100度 is put into 0.2kg of water at 20度. the final temperature of the mixture of copper and water is 35度. assume there is no heat loss to the surrounding. what is the specific heat capacity of copper??
最佳解答:
Energy loss by copper=Energy gained by water 0.5*specific heat capacity of copper *(100-35)=0.2*4200*(35-20) 32.5*specific heat capacity of copper =12600 specific heat capacity of copper =12600/32.5 =387.6(corr to 1 decimal place) **specific heat capacity of water=4200J/kg ℃ 2006-11-15 22:44:11 補充: sor~~answer should be 387.7(corr to 1 decimal place)
其他解答:
mcT=mcT 所有mixture只要將兩樣野既mcT =佢地,跟住就可以搵番剩低要既data 0.5kg(100度-35度)c=0.2kg(4200)(35度-20度) 50c-17.5c=29400-16800 32.5c=12600 c=388Jkg-1度-1(cor. to 3 sig.fig.) 2006-11-15 22:51:13 補充: specific heat capacity of water=4200Jkg-1度-1唔記得左講番佢地=既原因係:一開始copper比water熱所以copper有energy losswater就有energy gainenergy loss of copper=energy gain of water
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