呢條數點做
2017/07/04 11:55
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標題:
發問:
Peter has $9 more than Paul and Philip's os 1/3 of Peter's. How much money does each of them if they have a total of $61?
最佳解答:
Paul ==== X Peter ==== 9 + X Philip ====(9 + X)1/3 Paul+Peter+Philip = 61 X + (9 + X) + (9 + X)1/3 = 61 7/3X+12 = 61 7/3X = 49 X = 21 Paul has $21 2007-12-02 23:13:55 補充： Paul has$21Peter has 9 21 = $30Philip has (9 21)1/3 = 10 2007-12-02 23:14:35 補充： 打唔到個
其他解答:
Let Peter has 3x, then Paul has (3x-9) and Philip has x Since they have a total of $61, 3x+(3x-9)+x = 61 7x-9 = 61 7x = 70 x = 10 Therefore, Peter has 3 X 10 =$30, Paul has (3 X10) - 9 = $21, Philip has $10
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呢條數點做發問:
Peter has $9 more than Paul and Philip's os 1/3 of Peter's. How much money does each of them if they have a total of $61?
最佳解答:
Paul ==== X Peter ==== 9 + X Philip ====(9 + X)1/3 Paul+Peter+Philip = 61 X + (9 + X) + (9 + X)1/3 = 61 7/3X+12 = 61 7/3X = 49 X = 21 Paul has $21 2007-12-02 23:13:55 補充： Paul has$21Peter has 9 21 = $30Philip has (9 21)1/3 = 10 2007-12-02 23:14:35 補充： 打唔到個
其他解答:
Let Peter has 3x, then Paul has (3x-9) and Philip has x Since they have a total of $61, 3x+(3x-9)+x = 61 7x-9 = 61 7x = 70 x = 10 Therefore, Peter has 3 X 10 =$30, Paul has (3 X10) - 9 = $21, Philip has $10
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