chemical calculation (2)
2017/07/04 01:25
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chemical calculation (2)
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最佳解答:
Let there is 1 cm^3 of solution X. So, mass of solution X = 2.42 g Mass of X = 2.42 X 55% = 1.331 g Number of mole of X = Mass / Molar mass = 1.331 / 106 = 0.01256 mol Therefore, concentration of X in the solution = No. of mole / volume = 0.01256 / (1/1000) = 12.6 M (mol dm^-3)
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chemical calculation (2)
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Solution X has a density of 2.42gcm^-3 and contain 55% of X by mass. What s the conc. of X in the solution? (molar mass of X= 106g mol^-1)最佳解答:
Let there is 1 cm^3 of solution X. So, mass of solution X = 2.42 g Mass of X = 2.42 X 55% = 1.331 g Number of mole of X = Mass / Molar mass = 1.331 / 106 = 0.01256 mol Therefore, concentration of X in the solution = No. of mole / volume = 0.01256 / (1/1000) = 12.6 M (mol dm^-3)
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