F1 .Maths
2017/06/25 04:04
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1 The total cost for 88 adult tickets was $M293n.Since the printing machine was not functionin well ,the first and the last digits of total cost wrere missing from the receipt.find the cost of each tickets .2. It is knoen that 6-digits number A1527B is multiple of 4,and the remainder is 5 when it is divided by... 顯示更多 1 The total cost for 88 adult tickets was $M293n.Since the printing machine was not functionin well ,the first and the last digits of total cost wrere missing from the receipt.find the cost of each tickets . 2. It is knoen that 6-digits number A1527B is multiple of 4,and the remainder is 5 when it is divided by 11.Find the value of A +B . 3Find the smallest prime number that divides the number3的13次方+5的31次方 更新: Don't need to do Q1 . 更新 2: thank you for your help you are so helpful
最佳解答:
2. It is knoen that 6-digits number A1527B is multiple of 4,and the remainder is 5 when it is divided by 11.Find the value of A +B . Since A1527B is multiple of 4 7B is multiple of 6 B=6 remainder is 5 when it is divided by 11 A-1+5-2+7-1=0 (mod11) A=3 A+B=9 3Find the smallest prime number that divides the number3的13次方+5的31次方 3^13=1 (mod2) 5^31=1 (mod2) So 3^13+5^31=0 (mod2) the smallest prime number that divides the number3的13次方+5的31次方 is 2 A=1 2008-02-12 15:27:52 補充： Correction 7B is multiple of 4A=1 多餘了 2008-02-12 15:34:30 補充： 我覺得第一題好似只可以撞﹐但撞的話就不是數學。
其他解答:
1. M and n can be 1and 6 respectively. Total cost is $12936, if you purchase 147 tickets. 2. A and B can be 3 and 6 respectively, the avilable number may be 315276. 3. sorry... 2008-02-12 15:20:17 補充： sorry is for Q1the answer should be $147 for each ticket|||||吾識 . 不過幫你問緊人 ..
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F1 .Maths發問:
1 The total cost for 88 adult tickets was $M293n.Since the printing machine was not functionin well ,the first and the last digits of total cost wrere missing from the receipt.find the cost of each tickets .2. It is knoen that 6-digits number A1527B is multiple of 4,and the remainder is 5 when it is divided by... 顯示更多 1 The total cost for 88 adult tickets was $M293n.Since the printing machine was not functionin well ,the first and the last digits of total cost wrere missing from the receipt.find the cost of each tickets . 2. It is knoen that 6-digits number A1527B is multiple of 4,and the remainder is 5 when it is divided by 11.Find the value of A +B . 3Find the smallest prime number that divides the number3的13次方+5的31次方 更新: Don't need to do Q1 . 更新 2: thank you for your help you are so helpful
最佳解答:
2. It is knoen that 6-digits number A1527B is multiple of 4,and the remainder is 5 when it is divided by 11.Find the value of A +B . Since A1527B is multiple of 4 7B is multiple of 6 B=6 remainder is 5 when it is divided by 11 A-1+5-2+7-1=0 (mod11) A=3 A+B=9 3Find the smallest prime number that divides the number3的13次方+5的31次方 3^13=1 (mod2) 5^31=1 (mod2) So 3^13+5^31=0 (mod2) the smallest prime number that divides the number3的13次方+5的31次方 is 2 A=1 2008-02-12 15:27:52 補充： Correction 7B is multiple of 4A=1 多餘了 2008-02-12 15:34:30 補充： 我覺得第一題好似只可以撞﹐但撞的話就不是數學。
其他解答:
1. M and n can be 1and 6 respectively. Total cost is $12936, if you purchase 147 tickets. 2. A and B can be 3 and 6 respectively, the avilable number may be 315276. 3. sorry... 2008-02-12 15:20:17 補充： sorry is for Q1the answer should be $147 for each ticket|||||吾識 . 不過幫你問緊人 ..
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